$L \cdot \{\Lambda\} = \{\Lambda\} \cdot L = L$
$L \cdot \emptyset = \emptyset \cdot L = \emptyset$
$L \cdot M \neq M \cdot L$
$L \cdot (M \cdot N) = (L \cdot M ) \cdot N$
$L^0 = \{\Lambda\},\ L^n = L \cdot L^{n-1},\ if\ n > 0$
If L is a language of $\Sigma$ (i.e. $L \subset \Sigma^\ast$) then the closure of L is the language denoted by $L^\ast$
TODO: Positive closure