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theocs:lecture5-6 [2024/10/17 13:20] – [Pumping lemma] tamitheocs:lecture5-6 [2024/10/17 13:33] (current) – [Pumping lemma] tami
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 If we put $n$ into $m$ pigeonholes ($n>m$), then at least one pigeon hole must have more than one pigeon! If we put $n$ into $m$ pigeonholes ($n>m$), then at least one pigeon hole must have more than one pigeon!
 </WRAP> </WRAP>
 +
 +<WRAP center round info 60%>
 +**Theorem (Pumping Lemma)**
 +
 +Let $L$ be an infinite regular language accepted by a DFA with $m$, states. Then any string $w$ in $L$ with at least $m$ symbols can be decomposed as $w = xyx$ with $|xy| \leq m$, and $|y| \geq 1$ such that
 +
 +$$w_i = \underbrace{xy...yz}_i$$
 +
 +is also in $L$ for all $i = 0,1,2...$
 +</WRAP>
 +
 +**We can use the pumping lemma to prove a language is not regular**, but not that it is regular!
 +
 +We can prove **by contradiction** that $L = \{a^n b^n, n \geq 0 \}$ is not regular using the pumping lemma.
  
  
  • theocs/lecture5-6.1729171205.txt.gz
  • Last modified: 2024/10/17 13:20
  • by tami